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bootstrap: Remove check that identifies GNU compiler

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Bootstrapping no longer depends on this information.
This commit is contained in:
Daniel Pfeifer
2017-08-15 21:55:53 +02:00
parent 6fdcf02aaf
commit dc0befb6a1
1 changed files with 0 additions and 25 deletions
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25
bootstrap
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@@ -1110,31 +1110,6 @@ if [ "x${cmake_full_make_flags}" != "x${cmake_make_flags}" ]; then
echo "---------------------------------------------"
fi
# Ok, we have CC, CXX, and MAKE.
# Test C++ compiler features
# Are we GCC?
TMPFILE=`cmake_tmp_file`
echo '
#if defined(__GNUC__) && !defined(__INTEL_COMPILER)
#include <iostream>
int main() { std::cout << "This is GNU" << std::endl; return 0;}
#endif
' > ${TMPFILE}.cxx
cmake_cxx_compiler_is_gnu=0
if cmake_try_run "${cmake_cxx_compiler}" \
"${cmake_cxx_flags}" "${TMPFILE}.cxx" >> cmake_bootstrap.log 2>&1; then
cmake_cxx_compiler_is_gnu=1
fi
if [ "x${cmake_cxx_compiler_is_gnu}" = "x1" ]; then
echo "${cmake_cxx_compiler} is GNU compiler"
else
echo "${cmake_cxx_compiler} is not GNU compiler"
fi
rm -f "${TMPFILE}.cxx"
# Test for kwsys features
KWSYS_NAME_IS_KWSYS=0
KWSYS_BUILD_SHARED=0